x^2+12x-448=0

Solution for x^2+12x-448=0 equation:

x^2+12x-448=0

a = 1; b = 12; c = -448;
Δ = b2-4ac
Δ = 122-4·1·(-448)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-44}{2*1}=\frac{-56}{2}
=-28
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+44}{2*1}=\frac{32}{2}
=16
$